数字一定在减小）
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n为奇数，n×2+n×1+12n+n+1，这个一定为偶数，(2n+n+1)/2n+(n+1)/2，这里又有两种情况，为偶数，为奇数；为偶数就循环①（为偶数时数字一直在减小），一直到n+(n+1)/2为奇数
因为：n为奇数，有且只有(n+1)/2为偶数1n+(n+1)/2才能为奇数
n为奇数、n+(n+1)/2为奇数，下面继续：
n+(n+1)/2为奇数，×2+×1+12n+n+1+n+(n+1)/2+1，为偶数，除以
继续两种情况，为偶数，为奇数，为偶数就循环①、②，（反正偶数时数字在减小）
，一直到2n+1+(n+1)/4为奇数变换为
因为：n为奇数，n+1为偶数，有且仅有(n+1)/4为偶数，n+n+1+(n+1)/4才能为奇数
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